(4x^2-12x-40)/(x-5)

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Solution for (4x^2-12x-40)/(x-5) equation: 


D( x )

x-5 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x in (-oo:5) U (5:+oo)

(4*x^2-(12*x)-40)/(x-5) = 0

(4*x^2-12*x-40)/(x-5) = 0

4*x^2-12*x-40 = 0

4*(x^2-3*x-10) = 0

x^2-3*x-10 = 0

DELTA = (-3)^2-(-10*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+3)/(1*2) or x = (3-49^(1/2))/(1*2)

x = 5 or x = -2

4*(x+2)*(x-5) = 0

4*(x+2) = 0

x+2 = 0 // - 2

x = -2

x = -2

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